Question

Coefficient of linear expansion of steel and brass are 11 into 10 to the power minus 6019 into 10 to the power minus 6 respectively if there is difference in length at all temperature has to be keep constant at 30 cm the length at zero degree celsius should be

Answer 1

Answer:

Explanation:

Given Coefficient of linear expansion of steel and brass are 11 into 10 to the power minus 6019 into 10 to the power minus 6 respectively if there is difference in length at all temperature has to be keep constant at 30 cm the length at zero degree celsius should be

Δ L steel = Lo1 α steel ΔT

                  = 11 x 10^-6 ΔT

Δ L brass = Lo α brass ΔT  

                = 19 x 10^-6 ΔT

So steel = brass  

  Lo1 x 11 x 10^-6  ΔT = Lo2 x 19 x 10^-6 ΔT

 Length of steel at 0 degree / Length of brass at 0 degree = Lo1 / Lo2

                                                                                        = 19 x 10 ^-6 / 11 x 10^-6

                                                                                                    = 19 / 11