Question

coefficient of volume expansion of a liquid is 4.9 into 10 to the power of minus 4 per Kelvin calculate the fractional change in its density when the temperature is raised by 30 degree Celsius

Answer 1

Heya......!!!!

Given in the question :
=> Coefficient of volume expansion of glycerin, αV = 49 × 10^-4 K–1.

=> Rise in temperature, ΔT = 30°C.

As we know that Fractional change in its volume = ΔV/V .
Comparing this with Temprature we get ,,

Notations : m = Mass of glycerine
ρT1 = Initial density at T1
ρT2 = Initial density at T2

in place of ∆V I have written it = V1 and V2

=>> ΔV/V = αV ΔT
VT2 – VT1  =  VT1 αV ΔT
(m /ρT2)- (m /ρT1) = (m /ρT1)αV ΔT

=> Fractional Change in Density = (ρT1 – ρT2 ) / ρT2 

=> Putting values we Get ,, = 49 × 10^-4 × 30

49 × 10^-4 × 30 = 147 × 10^-3 .



Hope It Helps You ^_^

Answer 2

Answer:

Heya......!!!!

Given in the question :

=> Coefficient of volume expansion of glycerin, αV = 49 × 10^-4 K–1.

=> Rise in temperature, ΔT = 30°C.

As we know that Fractional change in its volume = ΔV/V .

Comparing this with Temprature we get ,,

Notations : m = Mass of glycerine

ρT1 = Initial density at T1

ρT2 = Initial density at T2

in place of ∆V I have written it = V1 and V2

=>> ΔV/V = αV ΔT

VT2 – VT1  =  VT1 αV ΔT

(m /ρT2)- (m /ρT1) = (m /ρT1)αV ΔT

=> Fractional Change in Density = (ρT1 – ρT2 ) / ρT2  

=> Putting values we Get ,, = 49 × 10^-4 × 30

49 × 10^-4 × 30 = 147 × 10^-3 .

Hope It Helps You ^_^

Explanation: