Question

Question no 5 ka answer plz

Answer 1

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0 \\ or. {( \sqrt{3}x )}^{2} - 2. \sqrt{3} x. \sqrt{2} + ({ \sqrt{2} }) ^{2} = 0 \\ or.( \sqrt{3} x - \sqrt{2})^{2} = 0 \\ or. \sqrt{3} x - \sqrt{2} = 0 \\ or. \: \: \: x = \sqrt{ \frac{2}{3} } ......answer...$
The required root is x = sq root(2/3)

Hope this is ur required answer

Answer 2

I m trying it

but it's seem wrong or some error
you wait for some time
oh yeah I got the mistake
the mistake is that root theirs no root on 2

Heya!!!

Here's your answer,

I m sending you a pic

hope it helps you