Physics, asked by rakshit2003, 1 year ago


Coeficient of performance of an ideal refrigerator working between temperature T, and T2
(T1 > T2) is​

Answers

Answered by abhijeet362
0

Answer:

COP= Q2/(Q1-Q2), applying the reversible refrigerator theory, Q can be replaced by temperature (100% Second Law Efficiency). so, COP > 1 (until T1> 2*T2). Generally T1 and T2 difference is less than T2 so efficiency is always greater than 1.

Answered by KajalBarad
0

coefficient of performance of an ideal refrigerator working between temperature T1 and T2 is Q2/Q1-Q2

Refrigerator(Also called as Reverse Heat Engine)

1.The main function of refrigerator is to cool and maintain the temperature of the body lower than atmospheric pressure.

2.It extracts heat from the cold and delivers it to atmosphere.

Now let the the Temperature of Cold body be T2

and let the Temperature of Hot body be T1 therefore  T1>T2

Let Q2 be Amount of Heat Taken from cold body and Q1 be Amount of Heat Taken from hot body.

Work done=Q1-Q2

Coefficient of performance= Amount of Heat taken from cold body / Work require to be done on system

= Q2/W

=Q2/Q1-Q2

Similar questions