Cofficient of x^2in expansion of ( x-2)^3
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(x-2)^3 = (x)^3 + 3 × (x)^2 × (-2) + 3 × x ×(-2)^2 + (-2)^3 considering x^2 part
3 × 4 ×x^2=12x^2
3 × 4 ×x^2=12x^2
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Hey mate ✌
↪ Here's your answer,
==> (x - 2)³ = x³ - (2)³ + 3(x)²(2) - 3(2)²(x)
.........{by using the identity
(a - b) ³ = a³ - 3(a)²(b) + 3(a)(b) ² - (b) ³}
==> x³ - 8 + 6x² - 12x
==> x³ + 6x² -12x -8
==> Here coefficient of x² is 6.
⭐ Hope it helps you ^_^ ⭐
↪ Here's your answer,
==> (x - 2)³ = x³ - (2)³ + 3(x)²(2) - 3(2)²(x)
.........{by using the identity
(a - b) ³ = a³ - 3(a)²(b) + 3(a)(b) ² - (b) ³}
==> x³ - 8 + 6x² - 12x
==> x³ + 6x² -12x -8
==> Here coefficient of x² is 6.
⭐ Hope it helps you ^_^ ⭐
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