Physics, asked by jayashrinivas5842, 11 months ago

coil having n turns and resistance RΩ is connected with a galvanometer of resistance 4RΩ. This combination is moved in time t seconds from a magnetic field W₁ weber to W₂ weber. The induced current in the circuit is
(a)  -\frac{W_2-W_1}{5Rnt}
(b)  -\frac{n(W_2-W_1)}{5Rnt}
(c)  -\frac{(W_2-W_1)}{Rnt}
(d)  -\frac{n(W_2-W_1)}{Rt}

Answers

Answered by abhi178
4
answer : option (b)  -\frac{n(W_2-W_1)}{5Rt}

number of turns of coil = n

resistance of the coil = R

resistance of galvanometer = 4R

change in magnetic flux in one turns of coil = W_2-W_1

so, total change in flux through coil = n(W_2-W_1)

we know, galvanometer is connected with coil in series combination so, Req = R +4R = 5R

now, induced emf = - change in flux/time

= - \frac{n(W_2-W_1)}{t}

now, induced current = \frac{\xi_{in}}{R_{eq}}

= -\frac{n(W_2-W_1)}{5Rt}

[ note : here, little mistake is done in typing option (b),  -\frac{n(W_2-W_1)}{5Rt} should be write in place of  -\frac{n(W_2-W_1)}{5Rnt}]
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