Coin is tossed twice.Find probability of getting atmost 1 Head?
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Answer:
3/4
Step-by-step explanation:
Total possible outcomes = 4 (HH, TT, HT, TH)
(Atmost one head = atleast one head)
Favorable outcomes = 3 (HH, HT, TH)
Probability = Favorable outcomes
____________________
Total no. of outcomes
= 3 /4
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