Coin of radius is 3cm , probability coin will completely land in the square
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The best way to look at the problem is to reformulate
The coin falls completely inside a single square.
to
The center of the coin is at least one coin radius from any grid line.
You can then shade the area of a grid square where the coin center cannot fall -- this shaded area will look the same in every square. If the coin radius is rr and the grid square sides have length dd, there's a small square of side length d−2r in each square where the center can fall without the coin extending beyond the grid square.
So the probablity of staying within the square becomes
(d−2r)^2/d^2assuming that the position of the coin's center relative to the square it happens to land on is uniformly distributed.Similar questions
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