Question

Cold water (cp= 480J/kg c) leading to a showen entors thin- walled double-pipe counter How heat exchanger at 15°c at of 0.28 kg/s and is heated to 45° c by hot water (cp= 4190 g J/kg) that enters at 100c at rate of 3kgls. If owall heat transfer coefficient is a 950 W/m² °C. Dotermine rate of heat transfer and heat transfer surface area of heat exchanges using E-NTU method​

Answer 1

Answer:

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Answer 2

Answer:

Cold water (cp = 4180 J/kg·K) leading to a shower enters a thin-walled double-pipe counter-flow heat exchanger at 15°C at a rate of 0.25 kg/s and is heated to 45°C by hot water (cp = 4190 J/kg·K) that enters at 100°C at a rate of 3 kg/s. If the overall heat transfer coefficient is 950 W/m2·K, determine the rate of heat transfer and the heat transfer surface area of the heat exchanger using the ε-NTU method. Answers: 31.35 kW, 0.482 m2

Given data:

Specific heat of hot water,

Specific heat of cold water,

Mass flow rate of cold water,

Mass flow rate of hot water,

Overall heat transfer coefficient

Explanation:

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