Math, asked by ritikkumar9618263248, 1 year ago

Collect the data for maximum and minimum temperature for last 20 days in the currentmonth.(1) Find the range of the data(ii) Find the mean deviation of the data(iii) Draw the frequency polygon based on this data(iv) On this frequency polygon, mark the day having maximum and minimum temperature.

Answers

Answered by namanmehra54
1
I think you should write this answer yourself

namanmehra54: I think you should write it yourself because this is activity based question
Vidayanaca: please
Answered by phillipinestest
6

Answer:

Mean deviation is 2.4

Step-by-step explanation:

First let us make a data for the temperatures.

27, 25, 29, 30, 34, 24, 27, 27, 23, 24, 24, 27, 23, 27, 24, 30, 34, 25, 29, 27

We will arrange this in ascending order, so we have

23, 23, 24, 24, 24, 24, 25, 25, 27, 27, 27, 27, 27, 27, 29, 29, 30, 30, 34, 34

So range is given by = h - l (highest - lowest)

    r = 34 - 23 or r = 11

To find mean deviation we need to find mean of the data.

  So, mean =\frac { (23+23+24+24+24+24+25+25+27+27+27+27+27+27+29+29+30+30+34+34) }{ 20 }

                  =\frac { 540 }{ 20 } =27

Formula to use is ∑\frac { (IX-\mu I) }{ NI }

Now we can write

     Value                            Distance from 27

       23                                        4

       23                                        4

       24                                        3

       24                                        3

       24                                        3

       24                                        3

       25                                        2

       25                                        2

       27                                        0

       27                                        0

       27                                        0

       27                                        0

       27                                        0

       27                                        0

       29                                        2

       29                                        2

       30                                        3

       30                                        3

       34                                        7

       34                                        7

Mean deviation = \frac { (4+4+3+3+3+3+2+2+0+0+0+0+0+0+2+2+3+3+7+7) }{ 20 } =\frac { 48 }{ 20 } =2.4

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