Combine 0.2 g atom of si with 21.3 g of cl find the empirical formula of the compound .
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step1:- divided both
element their atomic
weight
si :- given 0.2 g atom it
mean this is mole of Si
mole =weight/molecular weight
0.2=weight/28.8
weight=5.76g
now
Si :- 5.76/28.8=0.2
Cl:- 21.3g/35.5g=213/355=0.6
step2:-now take of
both element
Si:Cl=0.2:0.6=1:3
now we look here one
part of silicon react
with 3 part of chlorine
so, empirical
formula=SiCl3
element their atomic
weight
si :- given 0.2 g atom it
mean this is mole of Si
mole =weight/molecular weight
0.2=weight/28.8
weight=5.76g
now
Si :- 5.76/28.8=0.2
Cl:- 21.3g/35.5g=213/355=0.6
step2:-now take of
both element
Si:Cl=0.2:0.6=1:3
now we look here one
part of silicon react
with 3 part of chlorine
so, empirical
formula=SiCl3
abhi178:
please give my answer brainliest
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