combine 0.2g atom of silicon with 21.3g of chlorine,find the empirical formula of the compound formed
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data
mass of silicon=0.2g
mass of chlorine=21.3g
solution
percentage of silicon = 0.2divide 21.5x100
= 0.9%
percentage of carbon =21.3divide 21.5x 100
= 99%
step2
mole ratio of silicon = 0.9 divide 28
=0.03
mole ratio of carbon = 99 divide 12
= 8.25
step 3
simplest ratio of silicon= 0.03divide 0.03= 1
simplest ratio of carbon = 8.25 divide 0.03=275
empirical formula is Si275 C1
check it then asked me it is correct or wrong and also mention my mistake.
mass of silicon=0.2g
mass of chlorine=21.3g
solution
percentage of silicon = 0.2divide 21.5x100
= 0.9%
percentage of carbon =21.3divide 21.5x 100
= 99%
step2
mole ratio of silicon = 0.9 divide 28
=0.03
mole ratio of carbon = 99 divide 12
= 8.25
step 3
simplest ratio of silicon= 0.03divide 0.03= 1
simplest ratio of carbon = 8.25 divide 0.03=275
empirical formula is Si275 C1
check it then asked me it is correct or wrong and also mention my mistake.
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