English, asked by mrinmoypathgiri, 8 months ago

combine each set of sentences into a single santence​

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Answers

Answered by Anonymous
2

Question :-

Combine each set of sentences into a single sentence​

What should be used to get answer :-

Coordinating conjunctions

Answer :-

1. He is clever but not sincere

2. He is intelligent and hard working

3. I know him as a doctor

4. This is the boy to whom you teach english

5.  She likes dancing and singing

6. Stay here never get out of the place

7. Don't run in the sun orelse you will get attacked with fever

8. I have known him since I went to school

9. The doctor is very busy, so he can't examine any patient now

10. We returned homes till it grew dark

Additional Information :-

A coordinating conjunction is a word that joins two elements of equal grammatical rank and syntactic importance. They can join two verbs, two nouns, two adjectives, two phrases, or two independent clauses.

The seven coordinating conjunctions are FANBOYS

FANBOYS can be used to remember the coordinators for, and, nor, but, or, yet, and so.

Answered by surendragadhveer
1

Answer:

Solution

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Verified by Toppr

Let the tailor P work for x days and the tailor Q work for y days respectively.

Z=150x+200y

Here the problem can be formulated as an L.P.P. as follows

Minimize Z=150x+200y

Subject to the constraints

6x+10y≥60

⇒3x+5y≥30

4x+4y≥32

x+y≥8

and x≥0,y≥0

Converting them into equations we obtain the following equations

3x+5y=30,

⇒y=

5

30−3x

x 0 10 5

y 6 0 3

⇒x+y=8

y=8−x

x 0 8 5

y 8 0 3

The lines are shown on the graph paper and the feasible region (Unbounded convex) is shown shaded.

The corner points are

A(10,0),B(5,3) and C(0,8)

At the corner point the value of Z=150x+200y

At A(10,0)Z=1500

At B(5, 3), Z=150×5+200×3=750+600=1350

At C (0, 8), Z=1600

As the feasible region is unbounded, we draw the graph of the half-plane

150x+200y<1350

3x+4y<27

There is no point common with the feasible region, therefore, Z has minimum value.

Minimum value of Z is Rs. 1350 and it occurs at the point B(5,3).

Hence, the labour cost is Rs. 1350 when P works for 5 days and Q works for 3 days.

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