Question

Comment about the zeroes of a cubic polynomial whose linear and constant terms are absent

Answer 1

i)If b2-4ac is equal to zero, the equation has two real, equal or coincident roots.

Example: x2 + 4x + 4= 0; (x-2)2= 0, so, the two equal roots are 2, 2.

(ii)If b2-4ac < 0, then the equation has no real roots but a pair of complex roots which are not equal but are conjugates of each other.

Example: x2 + 4x + (25/4)=0; b2-4ac < 0; the roots are complex, namely: -2 + (3i/2) and –2 – (3 i/2).

(iii) If b2-4ac > 0 and is a perfect square, then the equation has two real distinct and     rational roots and f(x) can be resolved into two linear or rational factors of the first degree.dude i have right only those stuff which were written in my text book so dont delete my answer i have read the terms and condetion for this site and why u warned me