Question

Commercially available hcl contains 38% hcl by mass and has densityb1.19g/cm.Calculate molarity of the solution

Answer 1

Answer:

Explanation:

Molarity==%*d*10/gram molecular mass

=(38*1.19*10)/36.5

Answer 2

$\fbox{\texttt{\green{Answer:}}}$

Molarity of HCl = 12.39 M

$\fbox{\texttt{\pink{Given:}}}$

38% HCl by mass means that 38 g of HCl is present in 100 g of the solution.

Density = $\bold{1.19\:g\:cm^{-3}}$

$\fbox{\texttt{\blue{To\:find:}}}$

Molarity of HCl

$\fbox{\texttt{\red{How\:to\:Find:}}}$

38 g of HCl is present in 100 g of solution (given).

We know, $\bold{Density=\frac{Mass}{Volume}}$

Applying the given values, we get,

$\bold{1.19=\frac{100}{Volume}}$

$\therefore$ Volume of 100 g solution =

$\bold{\frac{100}{1.19}\:ml}$

$\therefore$ Strength of the solution =

$\bold{\dfrac{\dfrac{38}{100}}{1.19}\times{}1000}$

$\bold{=\dfrac{38\times{}1.19\times{}1000}{100}\:gL^{-1}}$

Molecular mass of HCl = $\bold{36.5}$

$\rule{200}4$

Molarity of HCl = $\bold{\dfrac{Strength\:of\:solution}{Molecular\:mass}}$

$\bold{=\dfrac{38\times{}1.19\times{}1000}{100\times{}36.5}}$

$\bold{=\dfrac{38\times{}11.9}{36.5}}$

$\bold{=12.39}$