Commercially available sulphuric acid is 98% by mass and has density of 2g/ml. calculate its mole fraction, molarity and molality.
Answers
Answer: The density should be
1.8g/ml but ma'am Seema gave 2g/ml
Explanation: Hi Ann Rose hope this will help you... (BTW IM GODWIN)
it is given that commercially available sulphuric acid is 98% by mass and has density of 2g/ml.
we have to find the mole fraction, molarity and molality.
here d = 2 g/ml, percentage of H₂SO₄ = 98%
molar mass of sulphuric acid, W = 98
molarity = 10 × d × percentage/W
= 10 × 2 × 98/98
= 20 Molar
given,sulphuric acid is 98% by mass.
so, mass of sulphuric acid = 98g
mass of solution = 100g
mass of water = 2g
molality = no of moles of solute/mass of solvent in kg
= (98/98)/(2/1000)
= 500 Molal
mole fraction = n₁/(n₁ + n₂)
= {98/98}/{2/18 + 98/98}
= 1/{1/9 + 1}
= 9/10
= 0.9
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