common salt obtain from seawater contains 96% by mass. the approximate number of molecules present in 10.0g of the Salt ?
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Answered by
1
100 g salt contains 95g NaCl
Therefore, 10g salt contains 9.5g NaCl
no. of molecules =(moles of NaCl) ×6.02×10
23
=
58.5
9.5
×6.02×10
23
= 10
Answered by
1
Answer:
of molecules present = 9.6 / 58.5 x 6.023 x 10^23 = 9.87 x 10^22 molecules.
Explanation:
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