Math, asked by skgt7709, 5 months ago

Company A produces 10% defective products, Company B produces 20% defective products and C produces 5% defective products. If choosing a company is an equally likely event, then find the probability that the product chosen is defective.​

Answers

Answered by gulabiyadav3
8

Answer:

35% defective product ans

Answered by SushmitaAhluwalia
4

Given: Percentage of defecctive products company A produces = 10%.

Percentage of defecctive products company B produces = 20%.

Percentage of defecctive products company C produces = 5%.

To find: The probability that the product chosen is defective

Solution: Let the event of selecting a particular company be P(E).

As such, P(E) = 1/3 since there are 3 companies.

And let the event of choosing a defective product be P(A).

Now the probability of choosing a defective product produced by A

= P(E) × P(A|E)

= (1/3) × (10/100)

Similarly, the probability of choosing a defective product produced by B

= P(E) × P(B|E)

= (1/3) × (20/100)

The probability of choosing a defective product produced by C

= P(E) × P(C|E)

= (1/3) × (5/100)

Therefore, the required probability that the product chosen is defective = P(A)

= (1/3) × (10/100) + (1/3) × (20/100) + (1/3) × (5/100)

= (10 + 20 + 5)/300

= 35/300

= 0.1167

= 0.12

Answer: 0.12

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