COMPARE KINETIC ENERGY OF PROTON WITH THAT OF ELECTRON . EACH HAS WAVELENGTH 1nm ?
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wavelength of proton = wavelength of electron,
thus,
momentum of proton = momentum of electron,
which implies, 2×mp×k.e.p = 2×me×(k.e.)e,
therefore, mp×(k.e)p = me×(k.e)e
k.e of proton / k.e of e- = me/mp.
thus,
momentum of proton = momentum of electron,
which implies, 2×mp×k.e.p = 2×me×(k.e.)e,
therefore, mp×(k.e)p = me×(k.e)e
k.e of proton / k.e of e- = me/mp.
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no ..wrong answer
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