Question

Find the value of 8sin(x/8)cos(x/2)cos(x/4)cos(x/8)

Answer 1

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Answer 2

Answer:

$sin x$

Step-by-step explanation:

Here, the given equation is

$8sin\dfrac{x}{8} cos\dfrac{x}{2} cos\dfrac{x}{4} cos\dfrac{x}{8}$

and find the minimum term

So, we know the formula of sin 2A

$2 sin A cos A= sin 2A$

apply this formula in the above equation and solve the equation, we get

$8sin\dfrac{x}{8} cos\dfrac{x}{8} cos\dfrac{x}{4} cos\dfrac{x}{2}\\4sin\dfrac{x}{4} cos\dfrac{x}{4} cos\dfrac{x}{2}\\2sin\dfrac{x}{2}cos\dfrac{x}{2}\\sinx$

sin x is the final answer.