Question

a man sold two buffaloes for rs 20,000 each. on one , he made a profit of 5% and on the other , he lost 10% . find his overall profit% and loss%.

Answer 1

c.p of first buffalo = c.p + 5%×c.p
c.p= x
x+5%×x=20,000
105x=20,000×100
x=20,000×100/105
x=19047.61
c.p of second buffalo= x_10%×x
x_10%×x= 20,000
90x= 20,000 ×100
x=20,000×100/90
x= 22,222.22
therfore = (22,222.22 +10947.61) _(20,000+20,000)
(sum of c.p) _(sum of s.p)
41,269.83 - 40,000
1,269.83
since c.p is greater than s.p there is a loss of rs 1,269.83
loss %=1,269.83 loss
--------- ×100 ----------×100
41,269.83 sum of c.p
3.07%

Answer 2

pls mark it as brain list