If Rd 510 be divided among A,B,C in such a way that A gets 2/3 of what B gets and B gets 1/4 of what c gets, find their respective shares.
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By the given conditions, we get
a+b+c = 510
b = 1/4 c
a = 2/3 into 1/4c = 1/6c
so,
1/6 c + 1/4 c+ c = 510
17/12 c = 510
c = 510 into 12/17 = 360
so b = 90 and a = 60
a+b+c = 510
b = 1/4 c
a = 2/3 into 1/4c = 1/6c
so,
1/6 c + 1/4 c+ c = 510
17/12 c = 510
c = 510 into 12/17 = 360
so b = 90 and a = 60
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