Question

Compare stability of o2 o2+ o2- on mot and indicate the magnetic prop.

Answer 1

The stability of following species can be decided on the basis of bond order as follows:

O2 : KK

Bond order =1/2(Nb-Na)

= 1/2(8-4)

= 2 = Paramagnetic

 

Similarly, the electronic configuration of O2+ can be written as:

Bond order of  O2+  = 1/2(8-3)

= 2.5 = paramagnetic

 

Electronic configuration of O2- ion will be:

Bond order of = 1/2(8-5)

= 1.5 = paramagnetic

 

Electronic configuration of O22- ion will be:

Bond order of O22- =1/2(8-6) = 1  diamagnetic

 

The larger the bond order,greater is the stability

Therefore the stability decreases as O2+  > O2 > O2- > O22-.

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Answer 2

Answer:

The Stability of following species can be decided on tha basis of bond order as follow :

O2:KK

Bond order = ½(Nb-Na)

= ½(8-4)

= 2 Paramagnetic

Similar, the electronic configuration of O2+ can be written as :

Bond Order of O2+ = ½(8-3)

= 2.5 Paramagnetic

Electronic configuration of O2- ion will be :

Bond Order of O2- = ½(8-5)

=1.5 Paramagnetic

Electronic configuration of O2²- ion will be :

Bond Order of O2²- = ½(8-6)

= 1 Diamagnetic

Hence,

The larger the bond order , grater is the stability.

Therefor the stability decrease as :

O2+ > O2 > O2- > O2²-

Hope it is useful to you !