Physics, asked by amanmulani0270, 7 months ago

compare the amount of work done in blowing a soap bubbles of radii in ratio 3:4​

Answers

Answered by sapnakumare27271
0

Explanation:

Given : Let R1 and R2 be the radii of two soap bubbles R1/R2=2/3 let o be the surface tension of soap bubble. Excess pressure inside bubble with radius R1=P1=40/R1 Excess pressure inside bubble with radius R2=P2=40/R2 P1/P2=[40/R1 ]xR2/40 =R2/R1 =3/1 =1.5 Work done in blowing soap bubble of radius R1=W1=o x 2x 4TR12 Work done in blowing soap bubble of radius R2=W2=o x 2x 4TTR22 W1/w2=o x 2x 4TTR12/o x 2x 4TR2?=(R1/ R2)°=(2/3)=4/9 Ratio of Workdone is 4:9

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