Math, asked by Danish200615, 4 months ago

Compare the following pairs of surds:

a) √ 27 , √ 41​

Answers

Answered by laibaayan80
2

Answer:

√27 < √ 41

Step-by-step explanation:

since, √27 = 3√3 = 3× 1.732 =5.196

and √41 = 6.40 (u can find this by division method easily)

so it is clear that, 5.196 < 6.40

therefore, √21 < √41... Ans.

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