Math, asked by sarthwangane13, 6 months ago

SOLVE:

(I)
X² + 2√3X + 3 = 0


(II)
(X/2) + (6/X) = 4


(III)
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+
)+
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=

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Answers

Answered by Alfa364
0

Answer:

(I) X=(-√3)

(ii) X=2,6

Answered by SuhaniiAgarwal
1

Answer:

i) x = - √3

ii) x = 2,6

Step-by-step explanation:

i) x² + 2√3x + 3 = 0

x² + √3x + √3x + 3 = 0

x (x + √3) + √3 (x + √3) = 0

(x + √3)² = 0

x + √3 = 0

x = - √3

ii) x/2 + 6/x = 4

x²+12 / 2x = 4

x² + 12 = 8x

x² - 8x + 12 = 0

(x - 6)(x - 2) = 0

x - 6 = 0

x = 6

x - 2 = 0

x = 2

Hope it helps you:)

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