SOLVE:
(I)
X² + 2√3X + 3 = 0
(II)
(X/2) + (6/X) = 4
(III)
(/
+
)+
(+/
)
=
/15
Answers
Answered by
0
Answer:
(I) X=(-√3)
(ii) X=2,6
Answered by
1
Answer:
i) x = - √3
ii) x = 2,6
Step-by-step explanation:
i) x² + 2√3x + 3 = 0
x² + √3x + √3x + 3 = 0
x (x + √3) + √3 (x + √3) = 0
(x + √3)² = 0
x + √3 = 0
x = - √3
ii) x/2 + 6/x = 4
x²+12 / 2x = 4
x² + 12 = 8x
x² - 8x + 12 = 0
(x - 6)(x - 2) = 0
x - 6 = 0
x = 6
x - 2 = 0
x = 2
Hope it helps you:)
Similar questions
Math,
2 months ago
Math,
2 months ago
Business Studies,
2 months ago
Math,
6 months ago
Math,
11 months ago
Chemistry,
11 months ago
CBSE BOARD XII,
11 months ago