Physics, asked by satyasurya999, 10 months ago

compare the kinetic energy of a football player of mass 40 kg at 1 m/s with the P.E of a spectator of mass 20 kg sitting on a gallery 1.2m above the ground level ( g=10m/s^2)​

Answers

Answered by muscardinus
7

E = 20 J  and P = 235.2 J

The potential energy of the spectator is more than the kinetic energy of a football player.

Explanation:

It is given that,

Mass of the player, m = 40 kg

Speed of the player, v = 1 m/s

Mass of the spectator, m' = 20 kg

Height at which it it placed, h = 1.2 m

Kinetic energy of the player is said to possessed due to its motion. It is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 40\times 1^2

E = 20 J

Due to the position of the spectator, potential energy will be possessed by it. It is given by :

P=m'gh

P=20\times 9.8\times 1.2

P = 235.2 J

So, the potential energy of the spectator is more than the kinetic energy of a football player. Hence, this is the required solution.

Learn more,

Kinetic and potential energy

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