Ratio of corresponding sides of two similar triangles is 2:5.if the area of the smaller triangle is 64sq cm,then what is the area of the bigger triangle?
Answers
Answered by
15
Solution :
*************************************
We know the theorem :
The ratio of the areas of two
similar triangles is equal to the
ratio of the squares of their
corresponding sides .
***********†***********************†*********
Here ,
Let A1 , A2 are areas of two similar
triangles and s1 , s2 are their
corresponding sides respectively ,
s1 : s2 = 2 : 5
=> s1/s2 = 2/5 -----( 1 )
A1 = 64 m² ,
A2 = ?
( s1/s2 )² = ( A1/A² )
=> ( 2/5 )² = ( 64 /A2 )
=> A2 = ( 64 × 25 )/4
= 16 × 25
= 400
Therefore ,
Area of bigger triangle ( A2 ) = 400m²
•••••
*************************************
We know the theorem :
The ratio of the areas of two
similar triangles is equal to the
ratio of the squares of their
corresponding sides .
***********†***********************†*********
Here ,
Let A1 , A2 are areas of two similar
triangles and s1 , s2 are their
corresponding sides respectively ,
s1 : s2 = 2 : 5
=> s1/s2 = 2/5 -----( 1 )
A1 = 64 m² ,
A2 = ?
( s1/s2 )² = ( A1/A² )
=> ( 2/5 )² = ( 64 /A2 )
=> A2 = ( 64 × 25 )/4
= 16 × 25
= 400
Therefore ,
Area of bigger triangle ( A2 ) = 400m²
•••••
Answered by
4
Answer:
mark as brain list answer
Attachments:
Similar questions