Compare the number of atoms in 16 grams oxygen(O2) and ozone(O3).
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Molecular mass of O3 is 16×3=48 . That means one mole of O3 will contain 48 grams.
Hence, 16 g of O3 will be equal to 1/3 moles.
Now acc to avogadro's Number “1 mole of any element is equal to 6 ×10°23 atoms”
So 1/3 moles of O3 will have 2×10°23 atoms
Another method
Molar mass of O3 will be 16 x3 =48 g .Here 16g 0f O3 is given so no of moles of O3 will be 16 ÷48 = 1/3 mole .now 1 mole = 3 ×6.022 ×10^23 oxygen atoms therefore 1/3 mole =6.022 ×1/3×3 ×10 ^23 no of atoms ..
=6.022 ×10^23 oxygen atoms
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