Question

compare the quadratic equation xaquare+9√3x+24=0 to ax squate+bx+ c

Answer 1

$Given \: equation: x^2 + 9 \sqrt{3} x + 24 = 0 \\ \\ comparing \: with \: a {x}^{2} + bx + c = 0 \\ \\ we \: get \\ \\ coefficient\ of\ x^2=a = 1 \\ coefficient\ of\ x=b =9 \sqrt{3} \\ constant\ term=c = 24$

Answer 2

x²+9√3x+24 = 0 (given)

Comparing with ax²+bx+c = 0

We get :-

Coefficient of x²=a=1

Coefficient of x=b=9√3

Constant term = c= 24

Mark it as brainliest answer....