Question

compare the rate of loss of heat from a metal spehere at 870°c with rate of loss of heat from same spehere at 427°c if temp. of surrounding is 27°c​

Answer 1

Answer:

3.2 degree celcius

Step-by-step explanation:

Answer 2

Answer:

heat loss by the first body is greater than the heat loss by the second body.

Step-by-step explanation:

rate of heat trensfer, H=(Tbody^4 - Tsurrounding^4)

T1 = 273 + 827 = 1100

T2 = 273 + 427 = 700

Tsurr = 273 +27 = 300

Thus , H1/H2 = T1^4 - Tsurr^4 / T2^4 - Tsurr^4

H1/H2 = (1100)^4 - (300)^4/ (700)^4 - (300)^4

=> 14641×10^8 - 81× 10^8

2401×10^8 - 81×10 ^8

= > 14560 = 6.27

2320 1

H1 = 6.27

H2 1

H1 = 6.27. and H2 = 1

H1 >H2

:. Heat loss by first body is greater than the heat lass hy the second bod.