Compare the strength of induced current when conductor moves :
i) parallel to the field lines ii) perpendicular to the field lines.
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Answer:
I)no emf. will be induced
ii)the induced current will be maximum
Answered by
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i)No EMF as l is parallel to B
ii) EMF e=Blv sin90 , so a current flows whose direction can be found by Right Hand Palm Rule.
ii) EMF e=Blv sin90 , so a current flows whose direction can be found by Right Hand Palm Rule.
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