Chemistry, asked by 01chanchal, 8 months ago

compare the thermodynamic efficiency to be expected when an engine operates between 1000k and 300k​

Answers

Answered by nirman95
1

Given:

Engine operates between 300 K and 1000 K.

To find:

The thermodynamic efficiency

Calculation:

Considering the sink temperature to be 300 K and source temperature to be 1000 K, we can say that:

Let efficiency be denoted by \eta.

\boxed{\bold{ \therefore \:  \eta = 1 -  \dfrac{  \theta_{sink}}{  \theta_{source}}}}

 =  >  \:  \eta = 1 -  \dfrac{300}{1000}

 =  >  \:  \eta = 1 -  \dfrac{3}{10}

 =  >  \:  \eta =  \dfrac{10 - 3}{10}

 =  >  \:  \eta =  \dfrac{7}{10}

Calculating efficiency in % :

 =  >  \:  \eta =  \dfrac{7}{10}  \times 100 \%

 =  >  \:  \eta =  70\%

So, efficiency of the thermodynamic engine is 70%.

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