Physics, asked by madhumasih1102, 10 months ago

compare the time period of two pendulum 2m and 18 m (9.8 m per square second)

Answers

Answered by captainahan

1

Answer:

2/6 sec

Explanation:

T1= 2π√2/9.8

T2= 2π√18/9.8

So, T1:T2 = 2:6 (by solving)

Hence T1/T2 = 2/6 sec

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