compare the time period of two pendulum 2m and 18 m (9.8 m per square second)
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Answer:
2/6 sec
Explanation:
T1= 2π√2/9.8
T2= 2π√18/9.8
So, T1:T2 = 2:6 (by solving)
Hence T1/T2 = 2/6 sec
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