compare the time period of two pendulums of length 1m and 9M
Answers
Answered by
29
Time period of pendulam is
T= 2π √(L÷g)
where L is the length of the pendulam.
g is the acceleration due to gravity.
so time period is proportional to the square root of the length.
if the two pendulam's time period is T(1) and T(2) and length L(1) and L(2) respectively then,
T(1) : T(2) = √L(1) : √L(2)
=√1 : √9
= 1 : 3
T= 2π √(L÷g)
where L is the length of the pendulam.
g is the acceleration due to gravity.
so time period is proportional to the square root of the length.
if the two pendulam's time period is T(1) and T(2) and length L(1) and L(2) respectively then,
T(1) : T(2) = √L(1) : √L(2)
=√1 : √9
= 1 : 3
Answered by
13
Answer:
1:3
Explanation:
given:
L1=1m and L2 =9 m
since T is proportional to √L
therefore T1/T2=√L1/L2
therefore T1/T2=√1/9
=1/3 i.e., T1:T2 =T1:T2
=1:3
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