Compare the time periods of two pendulums of length 9 m and 16 m.
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T1=2πg19
T2=2πg9=3×2πg1=3T1
therefore time period of second pendulum is thrice of first pendulum.
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Answer:
second is 3 times the time period of the first one...
Explanation:
T1=2πg1
T2=2πg9=3×2πg1=3T1
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