Compare the time periods of two simple pendulums of length 4m and 64 m at a place.
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Answer:
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Explanation:
T1 = 2pi√(1g) T2 = 2pi√(9g) = 3 × 2pi√(1g) = 3 T1 therefore time period of second pendulum is thrice of first pendulum
fazilahamed997:
I can't understand
oh I'm sorry but this is all my tchr taught me..... I don't have any other method
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Answer:
Time period 1:4
Explanation:
T=2π/√(l/g)
After Comparing T1 & T2 ratio of time is 1 : 4
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