Question

Compare the time periods of two simple pendulums of length 4 m and 1 m. In Ratio​

Answer 1

Answer:

I think this question answer is 4:1

Step-by-step explanation:

I hope it's helpful for you

Answer 2

Solution :

Given :-

Length of two pendulums are 4m and 1m respectively.

To Find :-

Relation between time period of both pendulums.

Concept :-

Time period is defined as time requires to complete one oscillation.

Formula of time period of simple pendulum in terms of length of pendulum and gravitational acceleration is given by

$\underline{\boxed{\bf{\pink{T=2\pi\sqrt{\dfrac{l}{g}}}}}}$

T denotes time period

l denotes length of pendulum

g denotes gravitational acceleration

Calculation :-

Since, gravitational acceleration is same for both, we can say that...

$\begin{gathered}\implies\bf\:\red{T\propto \sqrt{l}}\\ \\ \implies\sf\:\dfrac{T_1}{T_2}=\sqrt{\dfrac{l_1}{l_2}}\\ \\ \implies\sf\:\dfrac{T_1}{T_2}=\sqrt{\dfrac{4}{1}}\\ \\ \implies\boxed{\bf{\orange{T_1:T_2=2:1}}}\end{gathered}$