Complete combustion of 0.858 g of compound X gives 2.63 g of CO, and 1.28 g of H.O. The lowest
molecular mass X can have
(1) 43 g
(2) 86 g (3) 1299 (4) 1728
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Answers
Answered by
33
Answer:
1) mass of CO2 = 2.630 g or since the molar mass of CO2 is 44g / mole we have
2) 0.05976 moles of CO2 since there is 1 mole so C in CO2
3) we have 0.05976 moles of C or 0.718 g of C
mass of H2O = 1.280 g or since the molar mass of water is 18 g / mol
4) we have
0.07105 moles of H2O
since there are2 moles of H in 1 moles of H2O =
0.14210 moles of H or 0.143 g of H
5) molar ratio of C : H = 0.05976 : 0.14210
6) mass of C+H = 0.861 g
after dividing by the smallest 0.05976
molar ratio of C : H = 1.000 : 2.378
multiply by 3 to get whole numbers 3.000 7.134
empirical formula is C3H7
so minimum molar mass is 43g / mol
Answered by
6
Answer:
c3h7
Explanation:
here we multiply by 3 to convert it in simple ratio
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