Question

complete solution for this​

Answer 1

Hello mate....

Let y = 1/(1+ a + 1/b) + 1/(1+ b + 1/c) + 1/(1+ c + 1/a)

= b/(b + a.b + 1) + c/(c + b.c + 1) + a/(a + a.c + 1)

=[(b.(c + b.c + 1).(a + a.c + 1) + c.(b + a.b + 1).(a + a.c + 1) + a.(b + a.b + 1).(c + b.c + 1)]/(b + a.b + 1).(c + b.c + 1).(a + a.c + 1)

Expanding Numerator and denominator and putting a.b.c = 1 we have,

y = [6 + 3.a + 3.b + 3.c + 3.b.c + 3.a.b + 3.a.c + a.c^2 + c.b^2 + b.a^2]/[6 + 3.a + 3.b + 3.c + 3.b.c + 3.a.b + 3.a.c + a.c^2 + c.b^2 + b.a^2]

= 1

Hope this helps you.....