Complete solution of the inequality (x – 4) (x + 1)(x – 2) > 0 is
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Step-by-step explanation:
Given, (x1)
2
(x+1)
3
(x4)<0
Since square of a number cannot be <0
This means, one of (x+1)
3
or (x4) is <0
Now, (x+1)
3
<0 and x−4>0 => x<−1 and x>4 --- (1)
OR (x+1)
3
>0 and x−4<0 => x>−1 and x<4 --- (2)
From solutions of both possibilities, −1<x<4
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