Question

Complete the equations for the dissociation of the following acids

and bases in water. (follow example H2S ----à 2H+ + S)

a. H2SO4 ---à ……….. + …………

b. Mg(OH)2 ---à ………. + …………

c. HI ----à ……….. + ………….​

Answer 1

Answer:  

One definition is - (there are others, and you need to study those also) --  

an acid donates proton(s) (H+)

a base accepts protons

So in your equation, in the forward direction, the H2SO4 loses a proton (becomes HSO4-), so that is the ACID.  

[ your written question is missing this negative sign, HSO4-, but it needs it to be charged balanced, and to be correct.]  

The H2O accepts the proton (to become H3O+) so that is the base.

The CONJUGATE is what something becomes (what appears on the other side of the equation) in the acid/base reaction.  It is the "pair" to the original thing.  The only difference between something and its conjugate is a H+.

So H2SO4 (acid) loses a proton and becomes the conjugate base, HSO4-

If you consider the REVERSE reaction,  HSO4- is a base on the other side of equation - it is the thing that ACCEPTS the proton, so it would act as a BASE.  It is the conjugate base of H2SO4.

Answer 2

H2+ +SO42-

Mg2+ + 2OH-

H2 + I2