Math, asked by Anonymous, 9 months ago

Complete the following activity to solve the simultaneous equations.
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)​

Answers

Answered by BlackWizard
5

Answer:

5x + 3y = 9 -----(I)

2x − 3y = 12 ----- (II)

Add (I) and (II)

7x = 21

x = 3

Putting the value of x = 3 in (I) we get

5(3)+3y=9

⇒15+3y=9

⇒3y=9−15=−6

⇒y=−2

Thus, (x, y) = (3, −6).

Answered by shobhashinde8876
0

Answer:

(x,y) = (3,-2).

Step-by-step explanation:

5x+3y=9. ----(1)

2x-3y=12. ----(2)

Add equation (1) and (2),

5x+3y=9 + 2x-3y=12. =7x=21

7x=21

x=21/7

x=3.

substituting x=3 in equation (1),

5x+3y=9.

5×3+3y=9

15+3y. =9

3y. =9-15

3y. =(-6)

y. =(-6)/3

y. =(-2).

(x,y)=(3,-2) is the solution.

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