Complete the following activity to solve the simultaneous equations.
5x + 3y = 9 -----(I)
2x - 3y = 12 ----- (II)
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Answered by
5
Answer:
5x + 3y = 9 -----(I)
2x − 3y = 12 ----- (II)
Add (I) and (II)
7x = 21
x = 3
Putting the value of x = 3 in (I) we get
5(3)+3y=9
⇒15+3y=9
⇒3y=9−15=−6
⇒y=−2
Thus, (x, y) = (3, −6).
Answered by
0
Answer:
(x,y) = (3,-2).
Step-by-step explanation:
5x+3y=9. ----(1)
2x-3y=12. ----(2)
Add equation (1) and (2),
5x+3y=9 + 2x-3y=12. =7x=21
7x=21
x=21/7
x=3.
substituting x=3 in equation (1),
5x+3y=9.
5×3+3y=9
15+3y. =9
3y. =9-15
3y. =(-6)
y. =(-6)/3
y. =(-2).
(x,y)=(3,-2) is the solution.
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