Question

complete the following diagram, on a paper plss..
its from the lesson LIGHT REFLECTION AND REFLECTION (PHYSICS)

Answer 1

howdy, buddy

your answer is in the attachment given.

Answer 2

Answer:

(1) If a ray of light falling on the concave mirror passes through the center of the curvature, the reflected ray retraces its path.

(2) A virtual picture is created between the convex mirror's pole and focus when an object is put at a specific distance from the mirror. In comparison to the object, the image is smaller in size.

Explanation:

Consider the first diagram:

In the diagram, an incident ray of light is passing through the center of curvature of a concave mirror which strikes the mirror along the normal ray. The ray hits the mirror at an angle of $90^o$. Therefore, the incident ray coincides with the normal ray.

So, the angle of incidence $i=0$.

Now, according to the laws of reflection :

The angle of incidence is equal to the angle of reflection, i.e. ∠ i = ∠r.

∠r = 0

Hence, the reflected ray will retrace its path.

Consider the second diagram,

The object is placed at a finite distance from the convex mirror.

Two rays will be drawn from the object, the first ray is parallel to the principal axis and passes through the focus $F$ and the second ray from the object will pass through the center of curvature.

Since the convex mirror is a diverging mirror. The first ray when incident on the mirror will get reflected and we will back trace the reflected ray and pass it through the focus.

The second ray will also get reflected when an incident on the mirror will get reflected through the same path as it is trying to pass through the center of curvature. This ray is back-traced to the center of curvature.

Hence, the image of the object formed will be virtual, erect, and diminished.

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