complete the following in square method
1. 3x^{2}-5x+2=0
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3x²-5x+2
=> 3x²-(3x+2x)+2
=>3x²-3x-2x+2
=>(3x²-3x)+(-2x+2)
=>3x(x-1)-2(x-1)
=>(3x-2)(x-1)
Equating the equation with zero, we get,
(3x-2) = 0
3x = 2
x = 2/3
x-1 =0
x=1
Cheers!
kulsumbegum:
this is not a correct one
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