Question

Complete the following reactions:
(i) CH3COOH + NaOH →
(ii)
(iii) CH3OH + O2
(iv) CH2 = CH2 + Br →
(v) CH3COOC2H5 + NaOH →
(vi) CH2 = CH2 + H2O

Answer 1

Explanation:

in the first case there will be the formation of Acetic Acid salt of sodium ion and in the second the alcohol will be oxidised into aldehyde and then into Acetic Acid depending on the solvent or the reactants taken and the reaction half thin with women will be addition reaction and the next action of East with NH will form alcohol and acetic acid and the next reaction thing + water will be a addition reaction of S Plus and minus result into formation of of ethanol

Answer 2

Reactions

Explanation:

(i) CH3COOH + NaOH → CH3COONa + H2O

Acetic acid and sodium hydroxide to form sodium acetate and water.

(ii)  missing

(iii) CH3OH + O2 → CO2 + H2O

Methanol and oxygen liberates carbon dioxide and forms water.

(iv) CH2 = CH2 (g) + Br2 (aq) → C2H4Br2 (l)

Ethene reacts with bromine to form dibromoethane.

(v) CH3COOC2H5 + NaOH → C2H5OH + CH3COONa

Ethyl acetate reacts with sodium hydroxide to form sodium acetate and ethanol.

(vi) CH2 = CH2 + H2O → CH3CH2OH

Ethene reacts with water to form ethanol. The process is called hydrolysis.