. Complete the following tables and by inspection of the table, find
the solution of each equation :
x + 7 = 13
1
2
3
4
7
9
10
11
12
Answers
Answered by
1
Answer:
This implies that
x2+2ax=4x−4a−13
or
x2+2ax−4x+4a+13=0
or
x2+(2a−4)x+(4a+13)=0
Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.
Hence we get that
(2a−4)2=4⋅1⋅(4a+13)
or
4a2−16a+16=16a+52
or
4a2−32a−36=0
or
a2−8a−9=0
or
(a−9)(a+1)=0
So the values of a are −1 and 9.
Answered by
1
Step-by-step explanation:
x=13-7
x=6
the sln 6 is not thr
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