Science, asked by Techan2335, 11 months ago

Complete the following tables.
Mass (kg) Volume (m³) Density (kg/m³)
350 175 -
- 190 4

Density of Metal (kg/m³) Density of water (kg/m³) Relative Density
- 103 5
8.5 x 103 103 -

Weight (N) Area(m²) Pressure (Nm⁻²)
- 0.04 20,000
1500 500 -

Answers

Answered by aryandhingra05345
14

density of iron (Dr) = 7.8×10³ kg/m³

volume of iron piece(V) = 100cm³ = 10^(-4) m³

density of water (Dw) = 10³ kg/m³


(a) weight in air = Dr×V×g = 7.8×10³ × 10^(-4) ×10 = 7.8 N


(b) upthrust is the buoyant force exerted by water

   upthrust = Dw×V×g = 10³ × 10^(-4) ×10 = 1N


(c) apparent weight in water = weight in air - upthrust

                                        = 7.8N - 1N = 6.8N


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