Question

Completely factor the polynomial below.
16q^2+20q+6
A. (8q+3)(2q+1)
B. (8q+1)(2q+3)
C. 2(4q+3)(2q+1)
D. 2(4q+1)(2q+3)

Answer 1

Solution:-

given》

16q^2 + 20q +6

= 16^q^2 + 12q+8q +6

= 4q(4q+3) +2(8q+3)

= (4q+3)(4q+2)ans

Answer 2

16q² + 20q + 6

=> 16q² + (12+8)q + 6

=> 16q² + 12q + 8q + 6

=> 4q(4q+ 3) + 2(4q +3)

=> (4q + 3)(4q +2)

Hence, factorized.



I hope this will help you


-by ABHAY