Question

Completing
the
square
method:
6x²+11x+3=0​

Answer 1

Answer:

Step-by-step explanation:

6x^2+2x+9x+3 =0

2x(3x+1)+3(3x+1) =0

(2x+3)(3x+1) =0

their factor

x=-3/2 Or X=-1/3

Answer 2

$6 {x}^{2} + 11x + 3 = 0$

Divide the while equation by coefficient of x square.

$\frac{6 {x}^{2} }{6} + \frac{11x}{6} + \frac{3}{6} = 0 \\ {x}^{2} + \frac{11x}{6} + \frac{1}{2} = 0$

Transfer the fraction without variable to other side.

${x}^{2} + \frac{11x}{6} = \frac{ - 1}{2}$

Add (1/2 × coefficient of x)^2 to both sides.

${x}^{2} + \frac{11x}{12} + \frac{121}{144} = \frac{ - 1}{2} + \frac{121}{144} \\ \frac{144 {x}^{2} + 132x + 121 }{144} = \frac{ -72+121}{144} \\ 144 {x}^{2} + 132x + 121 = 49 \\ 144 {x}^{2} + 132x + 121 - 49 = 0 \\ 144 {x}^{2} + 132x + 72 = 0$

Now express it as a whole square equation and find the solution....

Seems that ur question is incorrect....plz check....or do as I directed......